(x^2+2x+2)(x-1)=0

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Solution for (x^2+2x+2)(x-1)=0 equation: 


Simplifying
(x2 + 2x + 2)(x + -1) = 0

Reorder the terms:
(2 + 2x + x2)(x + -1) = 0

Reorder the terms:
(2 + 2x + x2)(-1 + x) = 0

Multiply (2 + 2x + x2) * (-1 + x)
(2(-1 + x) + 2x * (-1 + x) + x2(-1 + x)) = 0
((-1 * 2 + x * 2) + 2x * (-1 + x) + x2(-1 + x)) = 0
((-2 + 2x) + 2x * (-1 + x) + x2(-1 + x)) = 0
(-2 + 2x + (-1 * 2x + x * 2x) + x2(-1 + x)) = 0
(-2 + 2x + (-2x + 2x2) + x2(-1 + x)) = 0
(-2 + 2x + -2x + 2x2 + (-1 * x2 + x * x2)) = 0
(-2 + 2x + -2x + 2x2 + (-1x2 + x3)) = 0

Combine like terms: 2x + -2x = 0
(-2 + 0 + 2x2 + -1x2 + x3) = 0
(-2 + 2x2 + -1x2 + x3) = 0

Combine like terms: 2x2 + -1x2 = 1x2
(-2 + 1x2 + x3) = 0

Solving
-2 + 1x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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